Any way to load then select

Widdershins Studio

I'd like to automate something in the script I am working on.

I've learnt how to load a model in script.

What I would like to do is after the model is loaded that it is selected. It would need to add to the current selections too.

Is there a way to do this, I've dug high and low, but to no avail.

Many thanks.

Richard Haseltine

What I do is use Scene.getNodeList() to get a list of waht's in the scene, and store it, then load my item, get a second copy of Scene.getNodeList() and run backwards through that until I find the item that isn't in the old list.

Widdershins Studio

Ahh that's clever thank for the tip 

Widdershins Studio

Tried this but it does not produce unique identifiers...

So say I have these duplicates in my scene pane:

item
item (2)
item (3)
item (4)

 

Because the base name was item...

   All I get out of it is item for each one.

So say I loaded another duplicate there's no way for me to isolate it.

Richard Haseltine

Don't look at the names or labels, compare the actual items (well, their pointers but since this is a script they look the same).

Richard Haseltine

I haven't tested this, just wrote  it from memory, but the general idea should be right

// get list of items before loadvar temp = Scene.getNodeList;// Make a list excluding bones, to save timevar olds = [];for ( var n = 0 ; n < temp.length ; n++ ) {	if ( ! temp[ n ].inherits( "DzBone" ) ) {		olds.push( temp[ n ] );	}}// Load your item(s)// get list of items after loadvar temp = Scene.getNodeList;// Make a list excluding bones, to save timevar news  = [];for ( var n = 0 ; n < temp.length ; n++ ) {	if ( ! temp[ n ].inherits( "DzBone" ) ) {		news.push( temp[ n ] );	}}var m;var newItems = [];// Check the new list against the oldfor ( n = 0; n < news.length ; n++ ) {	// m is the index, subtract one as it is zero based (one item means there is olds[ 0 ])	m = olds.length - 1;	while ( m >= 0 ) {		// if we find a match between old items and new, quit the checking		if ( news[ n ] == olds[ m ] ) {			break;		}		// If theer wasn't a match decrease m		m--;	}	// If the item is unique m will be -1 since the loop will not have stopped early	if ( m == -1 ) {		newItems.push( news[ n ] );	}}

 

Widdershins Studio

Thanks, I couldn't get push to work but it gave me some ideas